In the evening, the temperature is 2828 degrees. By midnight it has dropped 3131 degrees lower. Between midnight and 4 am, it goes down 66 more degrees. Then, by 9 am, the temperature goes up 3030 degrees.

Complete question :

In the evening, the temperature is 2828 degrees. By midnight it has dropped 3131 degrees lower. Between midnight and 4 am, it goes down 66 more degrees. Then, by 9 am, the temperature goes up 3030 degrees. Find the final temperature.

-38°

Step-by-step explanation:

Evening temperature = 28°

By midnight = 31° lower

4am = 66° lower

9 a.m = 30° higher

Temperature at midnight :

28° - 31° = - 2°

Temperature at 4 a.m:

-2° - 66° = - 68°

Final temperature at 9a.m :

-68° + 30° = - 38°

The temperature at 9a.m is - 38°

the dimensions are:

step-by-step explanation:

we want to find the dimensions of a rectangular box with volume of

we factor to obtain;

we rewrite the rightmost factor to obtain;

recall that:

we apply difference of two squares formula to obtain;

hence the dimensions are

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0