Reflect shape A in the line y=1

Step-by-step explanation:

1.Draw a mirrorline across y = 1 (Another way of saying that is draw a horizontal line through where y = 1)

2.For every single point of the shape, count the number of squares away that is from the mirror line on the graph, and from the mirror line go downwards by the amount of squares that you just counted from the mirrorline. Finally plot that point you reached with a cross and do the same with every point of the shape

3. Join all the cross together and there is your reflected shape.

*Extra Information*

If this was x = 1 instead of y = 1 you would reflect the shape horizontally instead of vertically (Youll see what i mean when the shape is reflected)

answer: standard form is ax^2 + bx + c = 0

step-by-step explanation:

standard form is ax^2 + bx + c = 0

(2x + 1)(x - 2) = 0

distribute to get into standard form

2x^2 - 4x + x - 2 = 0

2x^2 - 3x - 2 = 0

a = 2, b= -3, c = -2

a is your answer

#15. square

step-by-step explanation:

because quadrilatural (idk how to spell it) means somthing that is not 3d or like, equal sides (or somthing like that   you know what i meanz)

hope this halps!

bai!