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Mathematics, 24.03.2021 18:10 kerena8291

The graph of a parabola in the xy-plane has the following characteristics. It opens downward. It has an x-intercept at the point (5,0). Its vertex is at the point (2,18). Which of the following is the equation of the parabola? y=βˆ’2(x+1)(xβˆ’5) y equals, negative 2 times, open parenthesis, x plus 1, close parenthesis, times, open parenthesis, x minus 5, close parenthesis A y=βˆ’(x+1)(xβˆ’5) y equals, negative, open parenthesis, x plus 1, close parenthesis, times, open parenthesis, x minus 5, close parenthesis B y=βˆ’1821(xβˆ’5)(x+5) y equals, the negative fraction 18 over 21, end fraction, times, open parenthesis, x minus 5, close parenthesis, times, open parenthesis, x plus 5, close parenthesis C y=187(xβˆ’1)(x+5) y equals, the fraction 18 over 7, end fraction, times, open parenthesis, x minus 1, close parenthesis, times, open parenthesis, x plus 5, close parenthesis D Submit

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The graph of a parabola in the xy-plane has the following characteristics. It opens downward. It has...
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