An ant and a beetle are sitting at the south east corner of a rectangular picture frame. After a piece of sugar is placed on the north west corner they simultaneously start moving towards the sugar. The ant is moving around the frame 1.5 times faster than the beetle who is crossing the picture on a diagonal. If the length of the frame is 8 inches and the width is 1 inch more than half of diagonal, who will get to the sugar first? PL HELP

I'LL GIVE BRAINLIEST

10 and 9

Step-by-step explanation:

Ant will get there first, ant's path is 14 in, beetle's is 10 in.

Step-by-step explanation:

if the beetle's path is 10 inches (used Pythagorean theorem to find), we now know that:

Length = 8 in

Width = 1/2 (10) + 1 = 5+1 = 6

The ant moves around the frame, so 8 in +6 in = 14 in.

Hope this helps

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)

6x = 48

i hope this . 6 cards each and a total of $48. dvide each side by 6 and you will have your answer.