Will, micah and sue went to dinner. will paid 1/3 of the dinner bill. micah and sue paid in the ratio of 2: 5. if sue paid $6 more than will, how much did the dinner cost

Answer : The dinner cost was, $ 42

Step-by-step explanation :

Let the dinner cost be, 'x'

Dinner cost paid by Will =

Remaining dinner cost =

The ratio of dinner cost paid by Micah and sue is 2:5

Dinner cost paid by Micah =

Dinner cost paid by Sue =

As, Sue paid dinner cost $6 more than Will.

That means,

Thus, the dinner cost was, $ 42

-8/2y-8=5/y+4-7y+8/y^2-16

we move all terms to the left:

-8/2y-8-(5/y+4-7y+8/y^2-16)=0

we can not solve this equation