Help with question explain how you got it I’m confused?

haha u fixed it

Step-by-step explanation:

The equation of line a is y=(1/2)x−1, and it passes through point (6,2).

Line b is perpendicular to line a, and it passes through point (−6,2).

A: What is the slope of line b?

Perpendicular lines have slopes that are the negative reciprocal of each other. Since line a has a slope of (1/2), line b has a slope of -2. [note: this is:    - (1/(1/2))

B: What is the y-intercept of line b?

       line b is: y = -2x + c and we use point (-6,2) to find b.

      2 = -2(-6) + c

     14 = c

The equation for line b is: y = -2x + 14

The y-intercept (which is the point where x=0) is the point (0,14.)        So, y=14

we would need a picture of the quadrilateral in order to answer the question. also, it seems that the question is missing some components.