A private plane traveled from Seattle to a rugged​ wilderness, at an average speed of 132 mph. On the return​ trip, the average speed was 110 mph. If the total traveling time was 6 ​hours, how far is Seattle from the​ wilderness?

Brainliest PLEASE!

Step-by-step explanation:

a = seattle

b = wilderness

t = time traveling at 132 mph

(4-t) = time traveling at 110 mph

distance traveled at 132 mph = 132(t)

distance traveled at 110 mph = 110(4-t)

but the two distances are equal so:

132t = 110(4-t), solving for t

t = 1.82 hrs

d= 1.82 hrs * 132 m/hr = 240 miles

y= 2x+7

changed to y= 5x +7

as slope is increased from 2 to 5

therefore it would be less steeper

so, option d) is correct