What equations make c=9 a solution 1. 4-c=5
2. 20=14+c
3. 15=c-6
4. c/3=3
5. 36=4c

step-by-step explanation:

in the absence of parentheses, i will have to make some assumptions:   i interpret your (3x+5/y^6)(4y^3/5)​ to mean:

3x + 5     4y^(3/5)       (3x + 5)(4)

* =

    y^6             1               y^(6-3/5)

if this is not what you expected, repost your question using parentheses to indicate whether you meant

4y^3

    or   4y^(3/5)

    5

450

step-by-step explanation:

you get texts and minutes, so why not