Find two consecutive odd integers whose product is equal to 63​

If you need to see a systematic solution, let the 2 numbers be n and n + 2.

n(n + 2) = 63

n2 + 2n - 63 = 0

(n - 7)(n + 9) = 0

n = 7 or -9

If n = 7, then n + 2 = 9

If n = -9, then n + 2 = -7

This is based on knowledge of composite numbers: 7 times 9 = 63.

The only other pair of numbers satisfying this is -7 and -9

A bit confusing but hopes that helps out somewhat

step-by-step explanation:

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