Mhanifa please help! Explain how you can use the perpendicular bisector of a segment to draw an isosceles triangle.

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If you construct the perpendicular bisector of a line segment, every point on the perpendicular bisector will be the same distance from both point A and point B.

To construct an isosceles triangle, you can start from any point on the perpendicular bisector and draw line segments to point A and to point B

13

step-by-step explanation:

169-1=168

168-3=165

165-5=160

160-7=153

153-9=144

144-11=133

133-13=120

120-15=105

105-17=88

88-19=69

69-21=48

48-23=25

25-25=0

since it took 13times to completely subtract it hence its square root is 13

x = 2

step-by-step explanation:

if sr parallel to ba then the sides bc and ac are in proportion, that is

= ← substitute values

= ( cross- multiply )

27x = 6(4x + 1)

27x = 24x + 6 ( subtract 24x from both sides )

3x = 6 ( divide both sides by 3 )

x = 2