Yesterday morning at 8 a. m. the temperature was -14°F. At noon it was 10 degrees warmer. The temperature increase between noon and and 4 p. m. was twice the temperature increase between 8 a. m. and noon. What was the temperature at 4 p. m?

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16°

Step-by-step explanation:

so 10 degrees warmer from 8 to noon

so

-14°+10°= -4°

so at noon, it was -4°

but then from noon to 4 pm, the temp change was twice that

so

10° x 2= 20°

so

-4° + 20° = 16°

temp at 4 pm was 16°

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step-by-step explanation:

answer:   expression= p+p*d%

price reduction + sale price = $625

sale price: $p+$p*d%

where d% is the percentage of discount

step-by-step explanation:

original price = p

price went down by $150 price reduction $p*d%

sale price= $ 475

therefore the price before sale is: $625

and the expression that shows the price before sale is: p+p*d%