Suppose an electronics manufacturer knows from previous data that 2% of one type of an electronic component are defective. The quality control
inspector randomly selects components until a defective one is found. Is this
a binomial experiment? Why or why not?
A. This is not a binomial experiment, because the trials are not
independent.
B. This is not a binomial experiment, because the number of trials is
not fixed.
C. This is not a binomial experiment, because each trial cannot be
classified as a success or failure.
D. This is a binomial experiment, because the situation satisfies all
four conditions for a binomial experiment.

B.) This is not a binomial experiment, because the number of trials is not fixed.

Step-by-step explanation:

For a certain experiment to be classed as a binomial, it has to meet some criteria ;

Which include ;

1.) The trials should be independent.

11.) Each trial should be classifiable into one of success of failure.

111). There is a fixed mean probability for success and failure

IV) There is a fixed number of trials, in experiment described above, the number of trials isn't fixed, it is variable, as the trial will continue until a defective item is obtained.

the direct variation says that:

then the equation is of the form is given by:

            where k is the constant variation.

from the given table:

consider any value of x and m(x)=y

x = 2 and m(x)=y = 3

substitute these value in [1]; we have;

divide both sides by 2 we get;

⇒

check:

put x = -1 and m(x) = -1.5

substitute in the equation:

-1.5 = -1.5                   true

therefore, the function m(x) represents a direct variation

graph of this function as shown below:

were is the equation