PLESE SOMEONE HELP ME I DIDNT STUDY FOR THIS QUIZ

-6 ;

ax² + bx + c ;

-1

Step-by-step explanation:

1)

Give thequadratic equation :

4x² - 6x - 5

The values of a, b, c are the Coefficient of x², x and the constant respectively

Therefore, the value of b is the Coefficient of x = - 6

2.)

Standard form of a quadratic equation is :

ax² + bx + c

a = Coefficient of x² ; b = Coefficient of x ; c is a constant

3.)

2x² - 4x + 7

Axis of symmetry :

-b / 2a

a = 2 ; b = - 4, c = 7

-b / 2a = - 4 / 2(2)

= - 4 / 4

= - 1

i need the options

step-by-step explanation:

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15