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Mathematics, 22.03.2021 05:20 bartfrank447

What is the equation of a parabola that has a vertical axis, passes through the point (–1, 3), and has its vertex at (3, 2)? A) x= –y^2/16 + 6y/16–41/16

B) y= –x^2/16+6x/16–41/16

C) y=x^2/16–6x/16+41/16

D) x=y^2/16–6y/16+41/16

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