An equilateral triangle with side length 9 cm is shown in the diagram, work out the area of the triangle. Give your answer rounded to 1 DP.

The answer is 35.1 cm².

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Question:-

Find the area of an equilateral triangle with side length = 9cm correct upto one decimal place.

Solution:-

In an equilateral triangle all sides are equal.

Let s = side length = 9 cm

Then, area of equilateral triangle is given as:

A = (√3/4)s²

Putting the value of s here,

A = (√3/4) * (9 cm)²

=> A = (√3/4) * 81 cm²

=> A = √3 * 20.25 cm²

We know that, √3 = 1.732

=> A = 1.732 * 20.25 cm²

=> A = 35.073 cm²

Rounding to one decimal place,

=> A = 35.1 cm²

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions

include a picture of the drawing in order for me to

step-by-step explanation: