If the displacement of a particle is given by the formula S = 3t^3 - 20t^2 + 40t. Find (i) the displacement after 3 seconds (ii) the formula for the velocity at any time t (iii) the value of t when the particle is not moving (iv) the initial velocity of the particle (v) the formula for the acceleration at any time t (vi) the initial acceleration of the particle.​

I) displacement is s(3) = 81 - 180 +120

II) below. Iii) v= 0 when. 9t^2 -40t +40 = 0

IV) below. V) when t = 0 a(0) = -40

Step-by-step explanation: speed is first derivative of distance. V = s' (t)

V(t) = 9t^2 -40t +40

Acceleration is second derivative of distance. A= v'(t) = 18t -40

your answer is d 2,500

step-by-step explanation:

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