Triangle JKL has vertices at coordinates J(–2, 4), K(2, 4), and L(0, –2). What is the area of triangle JKL? A.
10 units2

B.
12 units2

C.
16 units2

D.
24 units2

c

Step-by-step explanation:

the answer is a

step-by-step explanation:

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet