A seed company planted a floral mosaic of a national flag. The perimeter of the flag is 2280. Determine the​ flag's width and length if the length is 300 ft greater than the width.

Step-by-step explanation:

Length = 50 feet

Width = 160 feet

Explanation:

I'm assuming the flagpole is not included in this question.

w

=

w

i

d

t

h

l

=

≤

n

>

h

The length compared to the width is:

w

=

l

+

110

<-- equation 1

The formula for perimeter:

P

=

2

w

+

2

l

420

=

2

w

+

2

l

<-- equation 2

Sub the first equation into the second.

420

=

2

(

l

+

110

)

+

2

l

Now you can solve for

l

algebraically.

420

=

2

l

+

220

+

2

l

4

l

=

200

l

=

50

Sub the found length into the first equation to find the length.

w

=

(

50

)

+

110

w

=

160

Therefore the flag is 50 feet long and 160 feet wide.

3 qrs + 3/2 xy hope this : /

step-by-step explanation:

the answer is "add 2y and y"

step-by-step explanation:

you need to collect the like terms first.