ANSWER ASAP GIVING BRAILIEST AND STUFF! Please answer the following essay question:
Suppose each dimension of a cube is increased. What happens to the surface area when each dimension is doubled, tripled or, quadrupled?

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cutt.ly/zxt1ipy

Step-by-step explanation:

Surface area of a cube = 6a²

When each dimension is doubled,  Side =2a

Surface area = 6*(2a)² = 6 * 4*a² = 4*(6a²)

So, when each dimension is doubled, surface area is 4 times of the original surface.

a = 3a

Surface area = 6*(3a)² = 6 * 9 *a² = 9 *6a²

                     = 9 times the original area

a = 4a

Surface area = 6*(4a)² = 6* 16 * a²

                     = 16 * (6a²)

                     = 16 times of original area

answer: 12

step-by-step explanation:

seems like d

step-by-step explanation: