In a certain country, the true probability of a baby being a boy is 0.519. Among the next nine randomly selected births in the country, what is the probability that at least one of them is a girl?

0.9973

Step-by-step explanation:

Given :

Probability of girl, probability of success , 1 - p = 1 - 0.519 = 0.481

1 - p = 0.481

n = 9

Probability that atleast one is girl

Usingbthe binomial probability distribution :

P(x =x) = nCx * p^x * (1 - p)^(n - x)

USing the binomial probability calculator :

p(x ≥ 1) = p(x=1) + p(x=2) + p(x=3) + p(x=4) + p(x=5) + p(x=6) + p(x=7) + p(x=8) + p(x=9)

p(x ≥ 1) = 0.9973 ( from calculator).

idk

step-by-step explanation:

i don't know

75

step-by-step explanation:

you do x-29=46 (the number of cantaloupes sold)

in order to find x, you have to find what minus 29 equals 46, meaning you'd have to add 29 to 46.

29+46=75

if you replace x with 75, the equation looks like:

75-29=46

x=75