In a javelin throw competition, five athletics score 56, 58, 63, 57 and 61 meters. What are their Mean and Median?

Mean = 59

Median = 58

Step-by-step explanation:

Given the data for a Javelin throw :

56, 58, 63, 57 61 meters

Reordering the data: 56, 57, 58, 61, 63

Mean, m = Σx / n

n = sample size = 5

m = (56 + 57 + 58 + 61 + 63) / 5

m = 295 / 5

m = 59

The median : 1/2 (n+1)th term

1/2(5 +1) the term

1/2(6) = 3rd term

Median value = 58

the length of o'p' is .

step-by-step explanation:

it is given that the quadrilateral m'n'o'p' is the image of quadrilateral mnop after dilation.

the center of dilation is origin and the scale factor is 1.5.

in dilation the image and preimge are similar figures. it means the sides of image and preimage are proportional.

the scale factor is defined as

the scale factor is 1.5.

multiply both sides by op.

note: if the value of op is given, then multiply the value of op with 1.5 to get the length of side o'p'.

therefore length of o'p' is .

let's solve your equation step-by-step.

24−3x=−27

step 1: simplify both sides of the equation.

24−3x=−27

24+−3x=−27

−3x+24=−27

step 2: subtract 24 from both sides.

−3x+24−24=−27−24

−3x=−51

step 3: divide both sides by -3.

−3x

−3

=

−51

−3

x=17

answer:

x=17

step-by-step explanation:

mark brainliest and have a great day!