Janine and her older sister Ingrid's ages are consecutive even numbers. When Janine's age is divided by seven, and Ingrid's age is divided by three, the sum of those numbers is fourteen. How old are Janine and Ingrid?

Janine is 28. Ingrid is 30.

Step-by-step explanation:

Let the ages be x and x + 2 for Janine and her sister, respectively.

x/7 + (x + 2)/3 = 14

Multiply both sides by the LCD, 21, to get rid of denominators.

21 * x/7 + 21 * (x + 2)/2 = 21 * 14

3x + 7(x + 2) = 294

3x + 7x + 14 = 294

10x = 280

x = 28

x + 2 = 30

Janine is 28. Ingrid is 30.

Janine is 28 and Ingrid is 30.

Step-by-step explanation:

Let Janine's age be x years , then Ingrid's age is x+2 years.

From the given information we have the equation:

x/7 + (x + 2)/3 = 14

Multiplying through by the LCM of 3 and 7 (21),  we have:

3x + 7(x + 2) = 294

10x + 14 = 294

10x =  294-14 = 280

x = 28, so:

Janine is 28 and Ingrid is 30.

10a^3+277a^2-132a-792

step-by-step explanation:

(2a+11)(5a-12)(foil)

=10a^2-24a+55a-132 =10a^2+31a-132

(10a^2+31a-132)(a+6)

=10a^3+60a^2+31a^2+186a^2-132a-792 =10a^3+277a^2-132a-792

i hope this is what you are looking for : )