Find the area of the shaded region. geometry please help if your good at it. will mark brainlist

Area of shaded region = area of circle - area of segment

(where "segment" refers to the unshaded region)

Area of circle = π (11.1 m)² ≈ 387.08 m²

The area of the segment is equal to the area of the sector that contains it, less the area of an isosceles triangle:

Area of segment = area of sector - area of triangle

130° is 13/36 of a full revolution of 360°.  This is to say, the area of the sector with the central angle of 130° has a total area equal to 13/36 of the total area of the circle, so

Area of sector = 13/36 π (11.1 m)² ≈ 139.78 m²

Use the law of cosines to find the length of the chord (the unknown side of the triangle, call it x) :

x ² = (11.1 m)² + (11.1 m)² - 2 (11.1 m)² cos(130°)

x ² ≈ 404.82 m²

x = 20.12 m

Call this length the base of the triangle. Use a trigonometric relation to determine the corresponding altitude/height, call it y. With a vertex angle of 130°, the two congruent base angles of the triangle each measure (180° - 130°)/2 = 25°, so

sin(25°) = y / (11.1 m)

y = (11.1 m) sin(25°)

y ≈ 4.69 m

Then

Area of triangle = xy/2 ≈ 1/2 (20.12 m) (4.69 m) ≈ 47.19 m²

so that

Area of segment ≈ 139.78 m² - 47.19 m² ≈ 92.59 m²

Finally,

Area of shaded region ≈ 387.08 m² - 92.59 m² ≈ 294.49 m²

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