Find the equation of the circle that has center (-4,3) and passes through 3,-3

(x+4)^2+(y-3)^2 = 85

Step-by-step explanation:

The standard form of equation of a circle is expressed as;

(x-a)^2 + (y-b)^2 = r^2

(a, b) is the center

r iis the radius

Get the radius

Radius is the distance between the two points

r^2 = (-3-3)^2 + (3-(-4))^2

r^2 - (-6)^2+(7)^2

r^2 = 36+49

r^2 = 85

Substitute (-4, 3) and r^2 = 85 into the formula

(x-(-4))^2 + (y-3)^2 = 85

(x+4)^2+(y-3)^2 = 85

This gives the required equation

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3