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In ATUV, the measure of _V=90°, the measure of ZT=66°, and TU = 93 feet. Find
the length of VT to the nearest tenth of a foot.
U
93
660
T
V
X

VT = 37.8 ft

Step-by-step explanation:

Here, we want to get the measure of VT

We need the diagram of the triangle here

We can get this in the attachment

From the diagram, we have it that the hypotenuse is the length UT since it faces the right angle

VT does not face the given angle , nor the right angle; this mean VT is the adjacent

Mathematically, the trigonometric ratio that connects the adjacent to the hypotenuse is the cosine

Thus;

cos 66 = VT/UT

cos 66 = VT/93

VT = 93 * cos 66

VT = 37.83

To the nearest tenth of a foot, VT = 37.8 ft

answer: download photomath it's legit.

step-by-step explanation:

you ignore the remainder, therefore the answer is y = x+2

step-by-step explanation:

you have to divide the denominator by the numerator. you can use synthetic division or long division.

[-5] .     1 .     7 .     11

x + 2 + 1/x+5