At a scrapbooking party, guests brought a certain number of photographs to use, based on how many pages they will be assembling. Ellie plans to assemble 4 small pages and 7 large
pages and brought a total of 22 photographs to use. Bridgette brought 30 photographs,
which is enough to assemble 8 small pages and 7 large pages. Assuming that the number of
photographs on a page remains constant, how many photographs fit on a small page and a
large page?
A small page can fit
photographs, and a large one can fit
photographs.

A small page can fit 2 photographs, and a large on can fit 2 photographs.

Step-by-step explanation:

Let the number of photographs on the small page be represented by m and that of large one by n.

Since the number of photographs on a page remains constant, then;

4m + 7n = 22 1

8m + 7n = 30 2

Multiply equation 1 by 2, and 2 by 1 to have;

8m + 14n = 44 3

8m + 7n = 30 4

subtract equation 4 from 3,

7n = 14

n = 2

Substitute the value of n in equation 1

4m + 7(2) = 22

4m + 14 = 22

4m = 8

m = 2

m = 2, n = 2

Therefore, a small page can fit 2 photographs, and a large on can fit 2 photographs so that the number of photographs n a page is constant.

5   1/4   miles per hour

step-by-step explanation:

15   3/4 / 3 = 5   1/4

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)