−x19x−5 where x≠0, 519
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Mathematics, 18.03.2021 03:40 jaelynnm
Given f(x)=4x2+19x−5 and g(x)=4x2−x.
What is (fg)(x)?
−x19x−5 where x≠0, 519
xx+5 where x≠0, 5
x+5x where x≠0, 14
−19x+5x where x≠0, 14
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You know the right answer?
Given f(x)=4x2+19x−5 and g(x)=4x2−x.
What is (fg)(x)?
−x19x−5 where x≠0, 519
−x19x−5 where x≠0, 519
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