In a survey of 706 parents with kids 4 to 8 years old. 346 say that they know their state booster seat law. Construct a 90% confidence interval for the population proportion.

(0.46, 0.52)

Step-by-step explanation:

The formula for Confidence Interval with Proportion

CI = p ± z × √p(1 - p)/n

Where

p = Proportion = x/n

x = 346

n = 706

p = 346/706

p = 0.49

z = z score of Confidence Interval 90% = 1.645

Therefore:

CI = 0.49 ± 1.645 × √0.49(1 - 0.49)/706

CI = 0.49 ± 1.645 × √0.49 × 0.51/706

CI = 0.49 ± 1.645 × 0.0188139843

CI = 0.49 ± 0.0309490042

Hence:

Confidence Interval is

0.49 - 0.0309490042

= 0.4590509958

≈ 0.46

0.49 + 0.0309490042

= 0.5209490042

≈ 0.52

Therefore , the confidence interval of the population proportion is

(0.46, 0.52)

the answer is a i belaeve atleast thats what my calculator just gfave me

step-by-step explanation:

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15