A bag contains 11 numbered chips inside. Two chips are labeled 1, three are labelled 2, and six are labelled 3. Let the random variable X = "number on a chip in the bag." What is the expected number of a chip that is randomly chosen from the bag?

2.36

Step-by-step explanation:

Using the μ=∑[x⋅P(X=x)

U will need to do

2/11 because you have 2 labeled 1

3/11 because you have 3 labeled 2

6/11 because you have 6 labeled 3

Then you will do:

1 x 2/11 = 0.18

2 x 3/11 = 0.5454 = 0.55

3 x 6/11 = 1.63

Then add them all together to find the μ

0.18 + 0.55 + 1.63 = 2.36

Hope that helps, plz put a good rating

the 4th choice is the correct one

step-by-step explanation:

i dont know if you cant find a way its best to actually add all of them start from 105 tho

step-by-step explanation: