Find number of possible 5-card hands that contain 3 face cards and 2 other cards (none of which are face cards) all 5 of the same suit

i think its 4

Step-by-step explanation:

there are 12 face cards in a deck and the rest are no faced. Since there is 3 face cards in each 5 card thing, 12/3 = 4. then you could just fit in any 2 no faced cards in since there are many. hope that helps

since proposition states that a number is greater than 25, if is true then the number must actually be greater than 25.

this implies that all possible options, except 24, can be accepted

don't know what that says sorry i can't you

step-by-step explanation:

idk what it says