( 15n2 - 5n + 45 ) ÷ 5​

I'm assuming we need to simplify this expression. (Tip when you are writing n squared, please write n^2, not n2.)

Since we can see that there is a 5 in each term inside the ( ), we simplify have to remove that if the whole thing is going to be divided by 5.

(15n^2-5n+45)/5

=3n^2-n+9

3n^2-n+9

Step-by-step explanation:

You would want to divide the 5 between each of the terms. 15n^2 ÷ 5 is 3n^2. 15 ÷ 5 is 3. The n^2 stays, so 3n^2. -5 ÷ 5 is -1. We don't have to worry about writing the -1. Rather, just write the -n, it is the same as writing -1n. Lastly, 45 ÷ 5 is 9. You have to put the terms together in standard form. Standard form is just writing the numbers from greatest power to least power. The 3n^2 would come first since 2 is the greatest power. Next would be the -n, and lastly the 9. The 9 is the constant, which always comes last. A constant would be a number without a variable after it, like 2x is not a constant but just 2 is. Therefore, the answer is 3n^2-n+9.

see explanation

step-by-step explanation:

a

(6r + 7) + (13 + 7r) ( remove brackets and collect like terms )

= 6r + 7 + 13 + 7r

= 13r + 20

b

remove brackets and collect like terms

13 - r - 1 + r

= 12 - r

c

remove brackets and collect like terms

= - 8 - r + 2r - 4

= - 12 + r

d

remove brackets and collect like terms

= 7r - - - 6r

[-   - = - - = - ]

= r -