Graph f(x)=4x2+20x+16​

f=2 x=2   i think srry if im wrong

Step-by-step explanation:

Direction: Opens Up

Vertex:  

(

−

5

2

,

−

49

)

Focus:  

(

−

5

2

,

−

783

16

)

Axis of Symmetry:  

x

=

−

5

2

Directrix:  

y

=

−

785

16

Select a few  

x

values, and plug them into the equation to find the corresponding  

y

values. The  

x

values should be selected around the vertex.

Tap for more steps...

x

y

−

4

−

40

−

3

−

48

−

5

2

−

49

−

1

−

40

0

−

24

Graph the parabola using its properties and the selected points.

Direction: Opens Up

Vertex:  

(

−

5

2

,

−

49

)

Focus:  

(

−

5

2

,

−

783

16

)

Axis of Symmetry:  

x

=

−

5

2

Directrix:  

y

=

−

785

16

x

y

−

4

−

40

−

3

−

48

−

5

2

−

49

−

1

−

40

0

−

24

image of graph

check the picture below.

well, the angle at the vertex d is clearly not a right-angle, let's check for the one at the vertex f which does look like,   however if it's indeed, that means ef is perpendicular to df, in which case their slopes will be negative reciprocal of each other.

so the negative reciprocal of the slope of ef is 1, however the slope of df is not 1, is 1/2, so nope, they're not perpendicular lines.

abde or 1,2,4, 5 is the answer

step-by-step explanation: