In Δ PQR, PQ = 17.4 m and PR = 7.6 m. K lies on QR such that ∠ PKQ = 137 °. find (i) ∠ QPR (ii) the length of QK using the trigonometric ratios

answer:   x = 3 + √11     and     x = 3 - √11

step-by-step explanation:

x² - 6x + 9 = 11

(x - 3)² = 11

x - 3 = ±√11

    x = 3 ± √11

x = 3 + √11     and     x = 3 - √11

a

step-by-step explanation:

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it is x equals 3   plese mark me really need it

step-by-step explanation:

the domain of a function is the set of input values, x , for which a function is defined. the domain is shown in the left oval in the picture below. the function provides an output value, f(x) , for each member of the domain.