The temperature at 6: 006: 00 a. m. was ‐3.5°c‐3.5°c. from 6: 006: 00 to 7: 007: 00, the temperature increased 2.5°c2.5°c. from 7: 007: 00 to 8: 008: 00, it decreased by 0.25°c0.25°c, and from 8: 008: 00 to 11: 0011: 00, the temperature dropped 3.25°c3.25°c. which expression shows the temperature in °c°c at 11: 0011: 00 a. m.?

-4.75 degree celsius

Step-by-step explanation:

We have to find  the temperature at 11:00 am

Temperature at 6:00 am =-3.5 degree celsius

Temperature increased from 6:00 to 7:00 by = 2.5 degrees celsius

Temperature at 7:00=-3.5+2.5=-1. degree celsius

The temperature decreased from 7:00 to 8:00 by =-0.25 degree celsius

Temperature at 8:00=-1.-0.25=-1.25 degree celsius

Temperature dropped from 8:00 to 11:00 by =3.35 degree celsius

Hence we take -3.5 degree celsius

Then the temperature at 11:00 am =-1.25-3.5=-4.75 degrees celsius

i use my brain for prombles like this maybe you could try it

step-by-step explanation:

6mm^3 or .6cm^3

      216

      /   \

  36     6

  /   \     /

6     6   6

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