The lifespan of brand A batteries is Normally distributed with a mean of 108 hours and a standard deviation of 12.5 hours. The lifespan of brand B batteries is Normally distributed with a mean of 92 hours and a standard deviation of

15.1 hours. A quality control specialist selects a random sample of 25 of each type of battery and calculates the

sample mean lifespan for each brand. Let 5, -ē, be the difference in the sample mean lifespan for each brand of

battery. What is the mean of the sampling distribution of the difference in sample means?

Do not round your answer.

you need more information to answer this question

step-by-step explanation:

your answer is a

step-by-step explanation:

4*4*4*4=256

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.