3. What are the intersection points of the line whose equation is y=3x +3 and the circle whose equation is (x - 2)² + y2 = 25?

Points of intersection of these graphs are (-2, -3) and (0.6, 4.8).

Step-by-step explanation:

Equation of the circle → (x - 2)² + y² = 25 ---------(1)

                                   → (x - 2)² + (y - 0)² = 5²

By comparing this equation with the standard equation of the circle,

(x - a)² + (y - b)²= r²

Here (a, b) is the center and r is the radius of the circle.

Therefore, center of the circle is (2, 0) and radius = 5 units

Second equation is a linear equation → y = 3x + 3 -------(2)

x-intercept of the equation → x = -1

y-intercept of the equation → y = 3

By graphing these equations we can get the point of intersections.

Solving these equations algebraically,

Substitute the value of y from equation (2) in the equation (1),

(x - 2)² + (3x + 3)² = 25

x² - 4x + 4 + 9x² + 18x + 9 = 25

10x² + 14x - 12 = 0

5x² + 7x - 6 = 0

x =

x =

x =

x = -2, 0.6

From equation (2),

y = -3, 4.8

Therefore, points of intersection of these graphs are (-2, -3) and (0.6, 4.8).

d. 9

step-by-step explanation:

in the table given in the picture, x is the input of the function and f(x) is the output on the given input. in the given table, it can be read as the value of function at -3 is it's respective value of f(x) which is -9.

as we have to find the value of f(3), we will see that what is the value of output on input 3. we can see in the table that the output value at x=3 is 9.

so, option d is the correct answer ..

7

step-by-step explanation:

the answer would be 7