Which expression is another way to write the expression shown here 5a+ 5b+ 5c+ 5d
5abcd
5a+bcd
5(a+b+c+d
(5a)(5b)(5c)(5d)

5(a+b+c+d)

Step-by-step explanation:

this is correct another way of writing this expression

because 5 is common to all and we can put it out

hope it helps

lockers 1, 4, 9, 16, 25, 40, and 49 are open

i ran through it by the other answer is wrong

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.