1. A recently hired MBA on the staff of Ace Systems thinks she can improve the training of production workers, who until now have been trained only on the job. She has developed three new alternative programs involving classroom sessions. These are compared, along with the existing procedure, as four methods or treatments: 1) On-the-job training only.
2) Classroom training only.
3) Heavy on-the-job training with light classroom work.
4) Light on-the-job training with heavy classroom work.
Each method is conducted with a different sample group of 8 randomly chosen trainees, who are given a placement examination upon completion. The investigator uses the scores on that test as the response variable. Statistical analysis provides the following sample means:
X-bar1 = 50.2. X-bar2 = 44.9. X-bar3 = 78.5. X-bar4 = 64.0
The SSE for the study is 8,431.31. Calculate the mean square treatment (MSTR).
a. 8,803.12.
b. 8,431.31.
c. 301.12.
d. none of the above.
2. If the computed F statistic for the study 6.03, how should the investigator conclude?
A. At alpha = 0.01, the critical value of F is 4.57. Therefore, the null hypothesis that
all training methods result in identical outcomes should be rejected.
B. At alpha = 0.01, the critical value of F is 10.85. Therefore, the null hypothesis that
all training methods result in identical outcomes should be rejected.
C. At alpha = 0.01, the critical value of F is 4.57. Therefore, the null hypothesis that
all training methods result in identical outcomes should not be rejected.
D. At alpha = 0.01, the critical value of F is 10.85. Therefore, the null hypothesis that
all training methods result in identical outcomes should not be rejected.
3. At alpha = 0.05, compute the Tukey Criterion appropriate for a pairwise comparison test. Choose the closest answer.
a. 6.1351.
b. 23.8044.
c. 125.9605.
d. 33.6645.