In ΔTUV, the measure of ∠V=90°, the measure of ∠U=38°, and VT = 6.1 feet. Find the length of UV to the nearest tenth of a foot.

step-by-step explanation:

in the absence of parentheses, i will have to make some assumptions:   i interpret your (3x+5/y^6)(4y^3/5)​ to mean:

3x + 5     4y^(3/5)       (3x + 5)(4)

* =

    y^6             1               y^(6-3/5)

if this is not what you expected, repost your question using parentheses to indicate whether you meant

4y^3

    or   4y^(3/5)

    5

i dont know nkw

step-by-step explanation:

kenffledkedncklzkdfeserw

80x^8−68x^6+16^5−20x^4−4x^3+8x^2

hope i'm right lol

32.5 is the answer i got thats the answer