A ball is thrown straight up from the top of a building 144 ft tall with an initial velocity of 48 ft per second. The height s(t) (in feet)
of the ball from the ground, at time t (in seconds), is given by
s(t) = 144 + 48t − 16t^2.
Find the maximum height attained by the ball.

180feet

Step-by-step explanation:

Given the function that models the height of a ball

s(t) = 144 + 48t − 16t^2.

At maximum height, the velocity is zero ie. ds/dt  = 0

ds/dt = 48 - 32t

0 = 48 - 32t

48 = 32t

t = 48/32

t = 1.5secs

Get the maximum height

s(t) = 144 + 48t − 16t^2.

s(1.5) = 144 + 48(1.5)-16(1.5)^2

s()1.5) = 144 + 72 - 16(2.25)

s(1.5) = 144 + 72-36

s(1.5) = 180 feet

Hence the maximum height attained by the ball is 180feet

b. would be the answer : )

step-by-step explanation:

step 1: add -16x to both sides.

16x−4y+−16x=64+−16x  

−4y=−16x+64

step 2: divide both sides by -4.

−4y /-4 = -16x + 64/-4

answer:   y=4x−16

hope i'm right

the car was traveling 40 mph before it started skidding. ( 2 points ) 17. was the driver were her brakes working at 75% efficiency or better? ( 2 points ) yes 29.

step-by-step explanation: