Use logarithmic differentiation to find dy/dx

How can I help you?
y
=
(
x
2
−
3
)
y
=
(
x
2
-
3
)
Find the Derivative - d/dx
Differentiate using the Power Rule,
d
d
x
[
x
n
]
=
n
x
n
−
1
d
d
x
[
x
n
]
=
n
x
n
-
1
.
2
x
2
x
Tap to view steps...
You are currently in the Algebra section, but it looks like you might be trying to do calculus. You might find more of the topics and symbols you need if you switch your subject over to Calculus.
y
=
(
x
2
−
3
)
y
=
(
x
2
-
3
)
Solve for y
Remove parentheses.
y
=
x
2
−
3
y
=
x
2
-
3
y
=
(
x
2
−
3
)
y
=
(
x
2
-
3
)
Graph
Graph the parabola using the direction, vertex, focus, and axis of symmetry.
Direction: Opens Up
Vertex:
(
0
,
−
3
)
(
0
,
-
3
)
Focus:
(
0
,
−
11
4
)
(
0
,
-
11
4
)
Axis of Symmetry:
x
=
0
x
=
0
Directrix:
y
=
−
13
4
y
=
-
13
4
x
y
−
2
1
−
1
−
2
0
−
3
1
−
2
2
1
xy-21-1-20-31-221
Tap to view steps...
image of graph
Tap to hide graph...
y
=
(
x
2
−
3
)
y
=
(
x
2
-
3
)
Find dy/dx
Differentiate each term with respect to
x
x
, then solve for
y
'
y
.
d
y
d
x
=
2
x