Six years ago a man's age was six times the age of his son. Four years hence, thrice his age will be equal to eight times his son's age. find their percent ages.​

THE SON IS 11 AND THE FATHER IS 36

Step-by-step explanation:

6 years ago ago a man's age was 6 times the age of his son. The product of the present ages of the father and his son is 396. What are their present ages?

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Welly Mulyadi

Answered 3 years ago

F= The present age of the father;

S= The present age of the son

F-6 = (S-6)6

FS = 396

From equation 1

F = 6S - 36 +6

F = 6S - 30

Insert this into equation 2

(6S-30)S= 396

6S^2 -30S - 396 = 0

Simplify this by dividing them by 6

Which results in

S^2 - 5S - 66 = 0

Then

(S-11)(S+5) = 0

So S=11 or S=-5

Since we’re looking for age so let’s take the positive number which is 11

Then insert S=11 to equation number 2

F(11)=396

F=396/11

F=36 so,

The present age of the son is 11 years old

And the present age of the father is 36 years old

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step-by-step explanation:

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