Estimated pet cat population for several European countries in 2002 are shown below. If each cat population doubles by 2010, which value will be the closest to the average pet cat population for these countries in 2010? A.) 9 million
B.)15 million
C.)18 million
D.) 12 million

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!

2,160 π

step-by-step explanation: