Which direction would the graph of y=|x-4|+3 open?

down
left
right
up

Up

Step-by-step explanation:

Let the parent function be y=|x|

Rule : f(x)→f(x-b)

So, the graph shifts right by b units

So, shift the parent graph by 4 units to right

So, using rule |x|→|x-4|

So, new function = |x-4|

Rule :f(x)→f(x)+b

So, the graph shifts up by b units

So, shift the obtained graph by 3 units up

So, |x-4|→|x-4|+3

Thus the direction of the graph of y=|x-4|+3 open is up

Hence Option D is correct.

step-by-step explanation:

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