How much should a retailer mark up his goods so that when he has a 50% off sale, the resulting prices will reflect prices will still reflect a 75% markup, (on his cost)

250%

Step-by-step explanation:

Let initial Markup % = x

Sales price = 100% + x = (1 + x)%

50% off sale = (1+x)% - (1+x)% /2

Final price after 50% off sale = 1 + 0.75 = 1.75

Hence,

50% off sale = 75% price markup

0.5(1 + x) = 1.75

0.5 + 0.5x = 1.75

0.5x = 1.75 - 0.5

x = 1.25 / 0.5

x = 2.5

Hence, Markup on initial price should be 1.25 = (2.5 * 100%) = 250%

the answer   is 200

step-by-step explanation:

this is a problem about poisson probabilities.   i don't know if you've

already studied poisson distributions, or if you have a place to look

to read more about the subject.  

here's how you can see a poisson distribution coming.   when there are

a lot of events that may happen at any time (or any place), and when

you're counting how many of them happen at a particular time (or a

particular place), and each event is independent of the others, then

the result is a poisson distribution.   this is roughly true for the

chocolate chips; one chip being in a cookie has only a small effect on

the probability that another chip will be in the cookie.

once you know you have a poisson distribution, you know a lot.   there

is only one parameter to a poisson distribution, so if you know the

mean, you know everything.   the form of the distribution is

  probability of n chips = {[e^(-x)]*(x^n)} / (n! )

step-by-step explanation: