Mark deposits $12000 into an account that pays 4% interest, compounded annually, for 5 years. Saul deposits $10000 into an account that pays 6% interest, compounded annually, for 8 years. Assuming no additional deposits are made, compare the interest earned on the accounts at the end of the interest period for each.

mark=$2400 &Saul=$4800

Step-by-step explanation:

For mark:

p=$12000

r=4%

t=5 years

I=prt/100

12000*4*5/100= 2400

For Saul:

p=$10000

r=6%

t=8 years

SI=prt/100

10000*6*8/100= 4800

the one that has a slope of 1/2 and is positive.

step-by-step explanation: 2 buckets 1 trip ; 4 buckets 2 trips and so on.

just do 5.2 + 2 ( 7.2) and 1/3 x 3 (.9) and youv'e got your equation. 0.9( 9/10) + 7.2 ^2 = 16.4 hope i could !

step-by-step explanation: