Help fast pls What is the surface area of the cylinder whose net is shown below? Use pi=3.

90 cm^2

72 cm^2

54 cm^2

63 cm^2

Step-by-step explanation:

length of rectangle = circumference of circle = πd = 6π cm

area of rectangle = 2×6π = 12π cm

area of one circle = πr² = 9π cm²

surface area = 12π + 2(9π) = 30π ≅ 90 cm²

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)