Help me Six years ago a man's age was six times the age of his son. Four years hence, thrice his age will be equal to eight times his son's age. find their percent ages.​

The present age of the father is 36 and the son is 6

x-6y=0

x-4y=12

-2y=-12

y=6

Let the present age of father's be x years and present age of son's be y years.

According to the problem

x=6y

After 4 years

x+4=4(y+4)

Hence we get two equations

x=6y (1)

x+4=4(y+4) (2)

Simplifying eq (2)

x+4=4y+16

x−4y=12

Put x=6y in eq (2), we get

6y−4y=12

2y=12

y=6 years

and x=6y=36 years

Present age of son =6 years

and present age of father =36 years

Step-by-step explanation:

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