In a certain algebra two class of 26 students 10 of them play basketball and five of them play baseball there are three students who play both sports what is the probability that a student chosen randomly from the class plays basketball baseball?

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3/26 students or 11% Pls give :)  

Step-by-step explanation:

probability dependant formula:P(A∪B)=P(A)+P(B)−P(A∩B)

P(a)= basketball

P(b)=baseball

so

P(AUB)=P(A)+P(B)-P(A∩B)= 18/26+5/26-20/26=3/26

3/26 or 11%  

OR you could solve this by adding all the sport/non sport #'s 18+5+6=29 and subtract 26 from 29

29-26=3

hence 3/26 students would randomly play basketball or baseball

Hope this Helps!

my acc plz

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32

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