A system of equations is created by using the line that is created by the equation 3 x minus 2 y = negative 4 and the line that is created by the data in the table below. x
y
–3
–9
–1
–5
3
3
5
7

What is the y-value of the solution to the system?

2 x + y = negative 3

Negative 2 x + y = negative 3

A 2-column table with 4 rows. Column 1 is labeled x with entries negative 1, 2, 3, 7. Column 2 is labeled y with entries 0, negative 3, negative 4, negative 8.
2 x + y = negative 3 and A 2-column table with 4 rows. Column 1 is labeled x with entries negative 1, 2, 3, 5. Column 2 is labeled y with entries 2, negative 1, negative 2, negative 4.
Negative 2 x + y = negative 3 and A 2-column table with 4 rows. Column 1 is labeled x with entries negative 1, 2, 3, 5. Column 2 is labeled y with entries 2, negative 1, negative 2, negative 4.
2 x + y = negative 3 and A 2-column table with 4 rows. Column 1 is labeled x with entries negative 1, 2, 3, 7. Column 2 is labeled y with entries 0, negative 3, negative 4, negative 8.
Negative 2 x + y = negative 3 and A 2-column table with 4 rows. Column 1 is labeled x with entries negative 1, 2, 3, 7. Column 2 is labeled y with entries 0, negative 3, negative 4, negative 8.